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Comment Re:Um..... (Score 1) 423

Here are a few calculations:

The proton rest mass of about 1GeV is 1.67x10^-27 kg the Schwarzschild Radius (Rs) of a black hole of a proton mass is then 2.48x10^-54 m. Now the total center of mass energy in the LHC is 14 TeV = 14,000 Gev so if ALL the center of mass rest energy were to enter the black hole (which is NOT possible - only a small fraction of the energy would go into the black hole), then the Rs of the 14TeV Black Hole would be 14,000 x 2.48 x 10^-54 m = 3.47 x 10^-50 m. Now for a quark to enter into the black hole, it would need to hit it almost head on -- so to be generous let's increase the radius by a factor of 10 to give Rs = 2.47 x 10^-49 m. But the radius of proton is 1.53 x 10^-18 m and there are only 3 quarks in a proton and maybe an average of 3 gluons. So the probability that this black hole would absorb one quark or gluon from a proton that it passes through would be Pr = (3 quarks + 3 glouns) * R(BH) ^ 2 / R(Proton) ^ 2 = 1.5 x 10^-61. Now there are only something like 10^+79 protons and neutrons in the entire observable universe and a measly 10^+51 protons and neutrons in the entire earth, so this black hole would have to pass through all the protons and neutrons in 10 billion earth masses before it would absorb one quark on average.

Indeed, since these tiny black holes hardly ever interact with matter, they could constitute the dark matter needed in cosmology - but ONLY if they do not evaporate.

So, once again, don't worry...

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